In the figure, FGHJ and GLMN are two rhombuses. If ∠LMN = 114° and ∠FJH = 102°, calculate
- ∠MLN
- ∠MHG
- ∠NPH
(a)
∠MLN
= (180° - 114°) ÷ 2
= 33° (Isosceles triangle)
(b)
∠MHG = ∠FJH = 102° (Corresponding angles)
(c)
∠NPH
= 102° - 33°
= 69° (Exterior angle of a triangle)
Answer(s): (a) 33°; (b) 102°; (c) 69°