In the figure, ABCD and BFGH are two rhombuses. If ∠FGH = 117° and ∠ADC = 96°, calculate
- ∠GFH
- ∠GCB
- ∠HJC
(a)
∠GFH
= (180° - 117°) ÷ 2
= 31.5° (Isosceles triangle)
(b)
∠GCB = ∠ADC = 96° (Corresponding angles)
(c)
∠HJC
= 96° - 31.5°
= 64.5° (Exterior angle of a triangle)
Answer(s): (a) 31.5°; (b) 96°; (c) 64.5°