In the figure, GHJK and HMNP are two rhombuses. If ∠MNP = 108° and ∠GKJ = 101°, calculate
- ∠NMP
- ∠NJH
- ∠PQJ
(a)
∠NMP
= (180° - 108°) ÷ 2
= 36° (Isosceles triangle)
(b)
∠NJH = ∠GKJ = 101° (Corresponding angles)
(c)
∠PQJ
= 101° - 36°
= 65° (Exterior angle of a triangle)
Answer(s): (a) 36°; (b) 101°; (c) 65°