In the figure, PQRS and QUVW are two rhombuses. If ∠UVW = 116° and ∠PSR = 102°, calculate
- ∠VUW
- ∠VRQ
- ∠WXR
(a)
∠VUW
= (180° - 116°) ÷ 2
= 32° (Isosceles triangle)
(b)
∠VRQ = ∠PSR = 102° (Corresponding angles)
(c)
∠WXR
= 102° - 32°
= 70° (Exterior angle of a triangle)
Answer(s): (a) 32°; (b) 102°; (c) 70°