In the figure, PQRS and QUVW are two rhombuses. If ∠UVW = 111° and ∠PSR = 92°, calculate
- ∠VUW
- ∠VRQ
- ∠WXR
(a)
∠VUW
= (180° - 111°) ÷ 2
= 34.5° (Isosceles triangle)
(b)
∠VRQ = ∠PSR = 92° (Corresponding angles)
(c)
∠WXR
= 92° - 34.5°
= 57.5° (Exterior angle of a triangle)
Answer(s): (a) 34.5°; (b) 92°; (c) 57.5°