In the figure, MNPQ and NSTU are two rhombuses. If ∠STU = 113° and ∠MQP = 100°, calculate
- ∠TSU
- ∠TPN
- ∠UVP
(a)
∠TSU
= (180° - 113°) ÷ 2
= 33.5° (Isosceles triangle)
(b)
∠TPN = ∠MQP = 100° (Corresponding angles)
(c)
∠UVP
= 100° - 33.5°
= 66.5° (Exterior angle of a triangle)
Answer(s): (a) 33.5°; (b) 100°; (c) 66.5°