In the figure, JKLM and KPQR are two rhombuses. If ∠PQR = 108° and ∠JML = 91°, calculate
- ∠QPR
- ∠QLK
- ∠RSL
(a)
∠QPR
= (180° - 108°) ÷ 2
= 36° (Isosceles triangle)
(b)
∠QLK = ∠JML = 91° (Corresponding angles)
(c)
∠RSL
= 91° - 36°
= 55° (Exterior angle of a triangle)
Answer(s): (a) 36°; (b) 91°; (c) 55°