In the figure, CDEF is a square and ∠DGF = 40°. Calculate
- ∠FHE
- ∠DFH
(a)
∠DHG
= 180° - 90° - 40°
= 50° (Angles sum of triangle)
∠FHE = 50° (Vertically opposite angles)
(b)
∠FDH = 90° ÷ 2 = 45°
∠DFH
= 180° - 40° - 90° - 45°
= 5° (Angles sum of triangle)
Answer(s): (a) 50°; (b) 5°