In the figure, ABCD is a square and ∠BED = 40°. Calculate
- ∠DFC
- ∠BDF
(a)
∠BFE
= 180° - 90° - 40°
= 50° (Angles sum of triangle)
∠DFC = 50° (Vertically opposite angles)
(b)
∠DBF = 90° ÷ 2 = 45°
∠BDF
= 180° - 40° - 90° - 45°
= 5° (Angles sum of triangle)
Answer(s): (a) 50°; (b) 5°