In the figure, CDEF is a square and ∠DGF = 38°. Calculate
- ∠FHE
- ∠DFH
(a)
∠DHG
= 180° - 90° - 38°
= 52° (Angles sum of triangle)
∠FHE = 52° (Vertically opposite angles)
(b)
∠FDH = 90° ÷ 2 = 45°
∠DFH
= 180° - 38° - 90° - 45°
= 7° (Angles sum of triangle)
Answer(s): (a) 52°; (b) 7°