In the figure, CDEF is a square and ∠DGF = 43°. Calculate
- ∠FHE
- ∠DFH
(a)
∠DHG
= 180° - 90° - 43°
= 47° (Angles sum of triangle)
∠FHE = 47° (Vertically opposite angles)
(b)
∠FDH = 90° ÷ 2 = 45°
∠DFH
= 180° - 43° - 90° - 45°
= 2° (Angles sum of triangle)
Answer(s): (a) 47°; (b) 2°