In the figure, PQRS is a square and ∠QTS = 43°. Calculate
- ∠SUR
- ∠QSU
(a)
∠QUT
= 180° - 90° - 43°
= 47° (Angles sum of triangle)
∠SUR = 47° (Vertically opposite angles)
(b)
∠SQU = 90° ÷ 2 = 45°
∠QSU
= 180° - 43° - 90° - 45°
= 2° (Angles sum of triangle)
Answer(s): (a) 47°; (b) 2°