In the figure, EFGH is a square and ∠FJH = 35°. Calculate
- ∠HKG
- ∠FHK
(a)
∠FKJ
= 180° - 90° - 35°
= 55° (Angles sum of triangle)
∠HKG = 55° (Vertically opposite angles)
(b)
∠HFK = 90° ÷ 2 = 45°
∠FHK
= 180° - 35° - 90° - 45°
= 10° (Angles sum of triangle)
Answer(s): (a) 55°; (b) 10°