In the figure, CDEF is a square and ∠DGF = 36°. Calculate
- ∠FHE
- ∠DFH
(a)
∠DHG
= 180° - 90° - 36°
= 54° (Angles sum of triangle)
∠FHE = 54° (Vertically opposite angles)
(b)
∠FDH = 90° ÷ 2 = 45°
∠DFH
= 180° - 36° - 90° - 45°
= 9° (Angles sum of triangle)
Answer(s): (a) 54°; (b) 9°