In the figure, ABCD is a square and ∠BED = 42°. Calculate
- ∠DFC
- ∠BDF
(a)
∠BFE
= 180° - 90° - 42°
= 48° (Angles sum of triangle)
∠DFC = 48° (Vertically opposite angles)
(b)
∠DBF = 90° ÷ 2 = 45°
∠BDF
= 180° - 42° - 90° - 45°
= 3° (Angles sum of triangle)
Answer(s): (a) 48°; (b) 3°