In the figure, CDEF is a quadrilateral where ∠CDE = 124° and ∠DEF = 120°. ∠EFG = 71° and DE = EF. The point G on CF is such that DG is parallel to EF. Calculate
- ∠DFG
- ∠DCG
(a)
∠EFD
= (180° - 120°) ÷ 2
= 30° (Isosceles triangle)
∠DFG
= 71° - 30°
= 41°
(b)
∠DCG
= 360° - 120° - 71° - 124°
= 45° (Sum of angles in a quadrilateral)
Answer(s): (a) 41°; (b) 45°