In the figure, KLMN is a quadrilateral where ∠KLM = 125° and ∠LMN = 110°. ∠MNP = 82° and LM = MN. The point P on KN is such that LP is parallel to MN. Calculate
- ∠LNP
- ∠LKP
(a)
∠MNL
= (180° - 110°) ÷ 2
= 35° (Isosceles triangle)
∠LNP
= 82° - 35°
= 47°
(b)
∠LKP
= 360° - 110° - 82° - 125°
= 43° (Sum of angles in a quadrilateral)
Answer(s): (a) 47°; (b) 43°