In the figure, KLMN is a quadrilateral where ∠KLM = 130° and ∠LMN = 120°. ∠MNP = 71° and LM = MN. The point P on KN is such that LP is parallel to MN. Calculate
- ∠LNP
- ∠LKP
(a)
∠MNL
= (180° - 120°) ÷ 2
= 30° (Isosceles triangle)
∠LNP
= 71° - 30°
= 41°
(b)
∠LKP
= 360° - 120° - 71° - 130°
= 39° (Sum of angles in a quadrilateral)
Answer(s): (a) 41°; (b) 39°