In the figure, PQRS is a quadrilateral where ∠PQR = 133° and ∠QRS = 118°. ∠RST = 74° and QR = RS. The point T on PS is such that QT is parallel to RS. Calculate
- ∠QST
- ∠QPT
(a)
∠RSQ
= (180° - 118°) ÷ 2
= 31° (Isosceles triangle)
∠QST
= 74° - 31°
= 43°
(b)
∠QPT
= 360° - 118° - 74° - 133°
= 35° (Sum of angles in a quadrilateral)
Answer(s): (a) 43°; (b) 35°