In the figure, TUVW is a quadrilateral where ∠TUV = 135° and ∠UVW = 110°. ∠VWX = 73° and UV = VW. The point X on TW is such that UX is parallel to VW. Calculate
- ∠UWX
- ∠UTX
(a)
∠VWU
= (180° - 110°) ÷ 2
= 35° (Isosceles triangle)
∠UWX
= 73° - 35°
= 38°
(b)
∠UTX
= 360° - 110° - 73° - 135°
= 42° (Sum of angles in a quadrilateral)
Answer(s): (a) 38°; (b) 42°