In the figure, CDEF is a quadrilateral where ∠CDE = 133° and ∠DEF = 118°. ∠EFG = 72° and DE = EF. The point G on CF is such that DG is parallel to EF. Calculate
- ∠DFG
- ∠DCG
(a)
∠EFD
= (180° - 118°) ÷ 2
= 31° (Isosceles triangle)
∠DFG
= 72° - 31°
= 41°
(b)
∠DCG
= 360° - 118° - 72° - 133°
= 37° (Sum of angles in a quadrilateral)
Answer(s): (a) 41°; (b) 37°