In the figure, JKLM is a quadrilateral where ∠JKL = 135° and ∠KLM = 110°. ∠LMN = 70° and KL = LM. The point N on JM is such that KN is parallel to LM. Calculate
- ∠KMN
- ∠KJN
(a)
∠LMK
= (180° - 110°) ÷ 2
= 35° (Isosceles triangle)
∠KMN
= 70° - 35°
= 35°
(b)
∠KJN
= 360° - 110° - 70° - 135°
= 45° (Sum of angles in a quadrilateral)
Answer(s): (a) 35°; (b) 45°