In the figure, FGHJ is a quadrilateral where ∠FGH = 135° and ∠GHJ = 110°. ∠HJK = 82° and GH = HJ. The point K on FJ is such that GK is parallel to HJ. Calculate
- ∠GJK
- ∠GFK
(a)
∠HJG
= (180° - 110°) ÷ 2
= 35° (Isosceles triangle)
∠GJK
= 82° - 35°
= 47°
(b)
∠GFK
= 360° - 110° - 82° - 135°
= 33° (Sum of angles in a quadrilateral)
Answer(s): (a) 47°; (b) 33°