In the figure, VWXY is a quadrilateral where ∠VWX = 131° and ∠WXY = 114°. ∠XYZ = 74° and WX = XY. The point Z on VY is such that WZ is parallel to XY. Calculate
- ∠WYZ
- ∠WVZ
(a)
∠XYW
= (180° - 114°) ÷ 2
= 33° (Isosceles triangle)
∠WYZ
= 74° - 33°
= 41°
(b)
∠WVZ
= 360° - 114° - 74° - 131°
= 41° (Sum of angles in a quadrilateral)
Answer(s): (a) 41°; (b) 41°