In the figure, HJKL is a quadrilateral where ∠HJK = 134° and ∠JKL = 112°. ∠KLM = 73° and JK = KL. The point M on HL is such that JM is parallel to KL. Calculate
- ∠JLM
- ∠JHM
(a)
∠KLJ
= (180° - 112°) ÷ 2
= 34° (Isosceles triangle)
∠JLM
= 73° - 34°
= 39°
(b)
∠JHM
= 360° - 112° - 73° - 134°
= 41° (Sum of angles in a quadrilateral)
Answer(s): (a) 39°; (b) 41°