In the figure, QRST is a quadrilateral where ∠QRS = 132° and ∠RST = 112°. ∠STU = 70° and RS = ST. The point U on QT is such that RU is parallel to ST. Calculate
- ∠RTU
- ∠RQU
(a)
∠STR
= (180° - 112°) ÷ 2
= 34° (Isosceles triangle)
∠RTU
= 70° - 34°
= 36°
(b)
∠RQU
= 360° - 112° - 70° - 132°
= 46° (Sum of angles in a quadrilateral)
Answer(s): (a) 36°; (b) 46°