In the figure, UVX and ZYlW are straight lines. ∠UZY = 46°, ∠ZUY = 48°, ∠VWX = 33° and ∠VXW = 104°. Find
- ∠UYV
- ∠YUV
(a)
∠UYZ
= 180° - 48° - 46°
= 86° (Angles sum of triangle)
∠UYV
= 180° - 86°
= 94° (Angles on a straight line)
(b)
∠XVW
= 180° - 104° - 33°
= 43° (Angles sum of triangle)
∠UVY = ∠XVW = 43° (Vertically opposite angles)
∠YUV
= 180° - 94° - 43°
= 43° (Angles sum of triangle)
Answer(s): (a) 94°; (b) 43°