In the figure, ABD and FElC are straight lines. ∠AFE = 47°, ∠FAE = 46°, ∠BCD = 37° and ∠BDC = 119°. Find
- ∠AEB
- ∠EAB
(a)
∠AEF
= 180° - 46° - 47°
= 87° (Angles sum of triangle)
∠AEB
= 180° - 87°
= 93° (Angles on a straight line)
(b)
∠DBC
= 180° - 119° - 37°
= 24° (Angles sum of triangle)
∠ABE = ∠DBC = 24° (Vertically opposite angles)
∠EAB
= 180° - 93° - 24°
= 63° (Angles sum of triangle)
Answer(s): (a) 93°; (b) 63°