In the figure, BCE and GFlD are straight lines. ∠BGF = 47°, ∠GBF = 47°, ∠CDE = 33° and ∠CED = 107°. Find
- ∠BFC
- ∠FBC
(a)
∠BFG
= 180° - 47° - 47°
= 86° (Angles sum of triangle)
∠BFC
= 180° - 86°
= 94° (Angles on a straight line)
(b)
∠ECD
= 180° - 107° - 33°
= 40° (Angles sum of triangle)
∠BCF = ∠ECD = 40° (Vertically opposite angles)
∠FBC
= 180° - 94° - 40°
= 46° (Angles sum of triangle)
Answer(s): (a) 94°; (b) 46°
