In the figure, PQS and UTlR are straight lines. ∠PUT = 46°, ∠UPT = 49°, ∠QRS = 34° and ∠QSR = 110°. Find
- ∠PTQ
- ∠TPQ
(a)
∠PTU
= 180° - 49° - 46°
= 85° (Angles sum of triangle)
∠PTQ
= 180° - 85°
= 95° (Angles on a straight line)
(b)
∠SQR
= 180° - 110° - 34°
= 36° (Angles sum of triangle)
∠PQT = ∠SQR = 36° (Vertically opposite angles)
∠TPQ
= 180° - 95° - 36°
= 49° (Angles sum of triangle)
Answer(s): (a) 95°; (b) 49°
