In the figure, CDF and HGlE are straight lines. ∠CHG = 50°, ∠HCG = 47°, ∠DEF = 39° and ∠DFE = 108°. Find
- ∠CGD
- ∠GCD
(a)
∠CGH
= 180° - 47° - 50°
= 83° (Angles sum of triangle)
∠CGD
= 180° - 83°
= 97° (Angles on a straight line)
(b)
∠FDE
= 180° - 108° - 39°
= 33° (Angles sum of triangle)
∠CDG = ∠FDE = 33° (Vertically opposite angles)
∠GCD
= 180° - 97° - 33°
= 50° (Angles sum of triangle)
Answer(s): (a) 97°; (b) 50°
