In the figure, DEG and JHlF are straight lines. ∠DJH = 48°, ∠JDH = 44°, ∠EFG = 30° and ∠EGF = 108°. Find
- ∠DHE
- ∠HDE
(a)
∠DHJ
= 180° - 44° - 48°
= 88° (Angles sum of triangle)
∠DHE
= 180° - 88°
= 92° (Angles on a straight line)
(b)
∠GEF
= 180° - 108° - 30°
= 42° (Angles sum of triangle)
∠DEH = ∠GEF = 42° (Vertically opposite angles)
∠HDE
= 180° - 92° - 42°
= 46° (Angles sum of triangle)
Answer(s): (a) 92°; (b) 46°
