In the figure, ABD and FElC are straight lines. ∠AFE = 45°, ∠FAE = 50°, ∠BCD = 30° and ∠BDC = 117°. Find
- ∠AEB
- ∠EAB
(a)
∠AEF
= 180° - 50° - 45°
= 85° (Angles sum of triangle)
∠AEB
= 180° - 85°
= 95° (Angles on a straight line)
(b)
∠DBC
= 180° - 117° - 30°
= 33° (Angles sum of triangle)
∠ABE = ∠DBC = 33° (Vertically opposite angles)
∠EAB
= 180° - 95° - 33°
= 52° (Angles sum of triangle)
Answer(s): (a) 95°; (b) 52°
