In the figure, EFH and KJlG are straight lines. ∠EKJ = 42°, ∠KEJ = 46°, ∠FGH = 36° and ∠FHG = 120°. Find
- ∠EJF
- ∠JEF
(a)
∠EJK
= 180° - 46° - 42°
= 92° (Angles sum of triangle)
∠EJF
= 180° - 92°
= 88° (Angles on a straight line)
(b)
∠HFG
= 180° - 120° - 36°
= 24° (Angles sum of triangle)
∠EFJ = ∠HFG = 24° (Vertically opposite angles)
∠JEF
= 180° - 88° - 24°
= 68° (Angles sum of triangle)
Answer(s): (a) 88°; (b) 68°