In the figure, CDF and HGlE are straight lines. ∠CHG = 45°, ∠HCG = 46°, ∠DEF = 29° and ∠DFE = 115°. Find
- ∠CGD
- ∠GCD
(a)
∠CGH
= 180° - 46° - 45°
= 89° (Angles sum of triangle)
∠CGD
= 180° - 89°
= 91° (Angles on a straight line)
(b)
∠FDE
= 180° - 115° - 29°
= 36° (Angles sum of triangle)
∠CDG = ∠FDE = 36° (Vertically opposite angles)
∠GCD
= 180° - 91° - 36°
= 53° (Angles sum of triangle)
Answer(s): (a) 91°; (b) 53°
