In the figure, ABD and FElC are straight lines. ∠AFE = 41°, ∠FAE = 47°, ∠BCD = 26° and ∠BDC = 104°. Find
- ∠AEB
- ∠EAB
(a)
∠AEF
= 180° - 47° - 41°
= 92° (Angles sum of triangle)
∠AEB
= 180° - 92°
= 88° (Angles on a straight line)
(b)
∠DBC
= 180° - 104° - 26°
= 50° (Angles sum of triangle)
∠ABE = ∠DBC = 50° (Vertically opposite angles)
∠EAB
= 180° - 88° - 50°
= 42° (Angles sum of triangle)
Answer(s): (a) 88°; (b) 42°
