In the figure, KLN and QPlM are straight lines. ∠KQP = 47°, ∠QKP = 44°, ∠LMN = 39° and ∠LNM = 117°. Find
- ∠KPL
- ∠PKL
(a)
∠KPQ
= 180° - 44° - 47°
= 89° (Angles sum of triangle)
∠KPL
= 180° - 89°
= 91° (Angles on a straight line)
(b)
∠NLM
= 180° - 117° - 39°
= 24° (Angles sum of triangle)
∠KLP = ∠NLM = 24° (Vertically opposite angles)
∠PKL
= 180° - 91° - 24°
= 65° (Angles sum of triangle)
Answer(s): (a) 91°; (b) 65°