In the figure, DEG and JHlF are straight lines. ∠DJH = 44°, ∠JDH = 41°, ∠EFG = 38° and ∠EGF = 111°. Find
- ∠DHE
- ∠HDE
(a)
∠DHJ
= 180° - 41° - 44°
= 95° (Angles sum of triangle)
∠DHE
= 180° - 95°
= 85° (Angles on a straight line)
(b)
∠GEF
= 180° - 111° - 38°
= 31° (Angles sum of triangle)
∠DEH = ∠GEF = 31° (Vertically opposite angles)
∠HDE
= 180° - 85° - 31°
= 64° (Angles sum of triangle)
Answer(s): (a) 85°; (b) 64°
