In the figure, BCE and GFlD are straight lines. ∠BGF = 47°, ∠GBF = 42°, ∠CDE = 29° and ∠CED = 111°. Find
- ∠BFC
- ∠FBC
(a)
∠BFG
= 180° - 42° - 47°
= 91° (Angles sum of triangle)
∠BFC
= 180° - 91°
= 89° (Angles on a straight line)
(b)
∠ECD
= 180° - 111° - 29°
= 40° (Angles sum of triangle)
∠BCF = ∠ECD = 40° (Vertically opposite angles)
∠FBC
= 180° - 89° - 40°
= 51° (Angles sum of triangle)
Answer(s): (a) 89°; (b) 51°
