In the figure, CDF and HGlE are straight lines. ∠CHG = 44°, ∠HCG = 40°, ∠DEF = 32° and ∠DFE = 102°. Find
- ∠CGD
- ∠GCD
(a)
∠CGH
= 180° - 40° - 44°
= 96° (Angles sum of triangle)
∠CGD
= 180° - 96°
= 84° (Angles on a straight line)
(b)
∠FDE
= 180° - 102° - 32°
= 46° (Angles sum of triangle)
∠CDG = ∠FDE = 46° (Vertically opposite angles)
∠GCD
= 180° - 84° - 46°
= 50° (Angles sum of triangle)
Answer(s): (a) 84°; (b) 50°