In the figure, UVX and ZYlW are straight lines. ∠UZY = 47°, ∠ZUY = 40°, ∠VWX = 27° and ∠VXW = 108°. Find
- ∠UYV
- ∠YUV
(a)
∠UYZ
= 180° - 40° - 47°
= 93° (Angles sum of triangle)
∠UYV
= 180° - 93°
= 87° (Angles on a straight line)
(b)
∠XVW
= 180° - 108° - 27°
= 45° (Angles sum of triangle)
∠UVY = ∠XVW = 45° (Vertically opposite angles)
∠YUV
= 180° - 87° - 45°
= 48° (Angles sum of triangle)
Answer(s): (a) 87°; (b) 48°
