In the figure, CDF and HGlE are straight lines. ∠CHG = 46°, ∠HCG = 50°, ∠DEF = 26° and ∠DFE = 117°. Find
- ∠CGD
- ∠GCD
(a)
∠CGH
= 180° - 50° - 46°
= 84° (Angles sum of triangle)
∠CGD
= 180° - 84°
= 96° (Angles on a straight line)
(b)
∠FDE
= 180° - 117° - 26°
= 37° (Angles sum of triangle)
∠CDG = ∠FDE = 37° (Vertically opposite angles)
∠GCD
= 180° - 96° - 37°
= 47° (Angles sum of triangle)
Answer(s): (a) 96°; (b) 47°
