In the figure, UVX and ZYlW are straight lines. ∠UZY = 43°, ∠ZUY = 41°, ∠VWX = 39° and ∠VXW = 102°. Find
- ∠UYV
- ∠YUV
(a)
∠UYZ
= 180° - 41° - 43°
= 96° (Angles sum of triangle)
∠UYV
= 180° - 96°
= 84° (Angles on a straight line)
(b)
∠XVW
= 180° - 102° - 39°
= 39° (Angles sum of triangle)
∠UVY = ∠XVW = 39° (Vertically opposite angles)
∠YUV
= 180° - 84° - 39°
= 57° (Angles sum of triangle)
Answer(s): (a) 84°; (b) 57°
