In the figure, KLN and QPlM are straight lines. ∠KQP = 43°, ∠QKP = 43°, ∠LMN = 31° and ∠LNM = 120°. Find
- ∠KPL
- ∠PKL
(a)
∠KPQ
= 180° - 43° - 43°
= 94° (Angles sum of triangle)
∠KPL
= 180° - 94°
= 86° (Angles on a straight line)
(b)
∠NLM
= 180° - 120° - 31°
= 29° (Angles sum of triangle)
∠KLP = ∠NLM = 29° (Vertically opposite angles)
∠PKL
= 180° - 86° - 29°
= 65° (Angles sum of triangle)
Answer(s): (a) 86°; (b) 65°
