In the figure, PQS and UTlR are straight lines. ∠PUT = 41°, ∠UPT = 47°, ∠QRS = 33° and ∠QSR = 114°. Find
- ∠PTQ
- ∠TPQ
(a)
∠PTU
= 180° - 47° - 41°
= 92° (Angles sum of triangle)
∠PTQ
= 180° - 92°
= 88° (Angles on a straight line)
(b)
∠SQR
= 180° - 114° - 33°
= 33° (Angles sum of triangle)
∠PQT = ∠SQR = 33° (Vertically opposite angles)
∠TPQ
= 180° - 88° - 33°
= 59° (Angles sum of triangle)
Answer(s): (a) 88°; (b) 59°
