In the figure, BCE and GFlD are straight lines. ∠BGF = 50°, ∠GBF = 43°, ∠CDE = 37° and ∠CED = 115°. Find
- ∠BFC
- ∠FBC
(a)
∠BFG
= 180° - 43° - 50°
= 87° (Angles sum of triangle)
∠BFC
= 180° - 87°
= 93° (Angles on a straight line)
(b)
∠ECD
= 180° - 115° - 37°
= 28° (Angles sum of triangle)
∠BCF = ∠ECD = 28° (Vertically opposite angles)
∠FBC
= 180° - 93° - 28°
= 59° (Angles sum of triangle)
Answer(s): (a) 93°; (b) 59°
