In the figure, NPR and TSlQ are straight lines. ∠NTS = 40°, ∠TNS = 50°, ∠PQR = 33° and ∠PRQ = 115°. Find
- ∠NSP
- ∠SNP
(a)
∠NST
= 180° - 50° - 40°
= 90° (Angles sum of triangle)
∠NSP
= 180° - 90°
= 90° (Angles on a straight line)
(b)
∠RPQ
= 180° - 115° - 33°
= 32° (Angles sum of triangle)
∠NPS = ∠RPQ = 32° (Vertically opposite angles)
∠SNP
= 180° - 90° - 32°
= 58° (Angles sum of triangle)
Answer(s): (a) 90°; (b) 58°
