In the figure, UVX and ZYlW are straight lines. ∠UZY = 44°, ∠ZUY = 44°, ∠VWX = 40° and ∠VXW = 115°. Find
- ∠UYV
- ∠YUV
(a)
∠UYZ
= 180° - 44° - 44°
= 92° (Angles sum of triangle)
∠UYV
= 180° - 92°
= 88° (Angles on a straight line)
(b)
∠XVW
= 180° - 115° - 40°
= 25° (Angles sum of triangle)
∠UVY = ∠XVW = 25° (Vertically opposite angles)
∠YUV
= 180° - 88° - 25°
= 67° (Angles sum of triangle)
Answer(s): (a) 88°; (b) 67°