In the figure, FGJ and LKlH are straight lines. ∠FLK = 46°, ∠LFK = 43°, ∠GHJ = 27° and ∠GJH = 108°. Find
- ∠FKG
- ∠KFG
(a)
∠FKL
= 180° - 43° - 46°
= 91° (Angles sum of triangle)
∠FKG
= 180° - 91°
= 89° (Angles on a straight line)
(b)
∠JGH
= 180° - 108° - 27°
= 45° (Angles sum of triangle)
∠FGK = ∠JGH = 45° (Vertically opposite angles)
∠KFG
= 180° - 89° - 45°
= 46° (Angles sum of triangle)
Answer(s): (a) 89°; (b) 46°
