In the figure, DEG and JHlF are straight lines. ∠DJH = 40°, ∠JDH = 45°, ∠EFG = 27° and ∠EGF = 109°. Find
- ∠DHE
- ∠HDE
(a)
∠DHJ
= 180° - 45° - 40°
= 95° (Angles sum of triangle)
∠DHE
= 180° - 95°
= 85° (Angles on a straight line)
(b)
∠GEF
= 180° - 109° - 27°
= 44° (Angles sum of triangle)
∠DEH = ∠GEF = 44° (Vertically opposite angles)
∠HDE
= 180° - 85° - 44°
= 51° (Angles sum of triangle)
Answer(s): (a) 85°; (b) 51°
